Blauberg KFK 80x50-3
- Designation key
- Air pressure losses
- Calculation diagram
Supply air cooling for ventilation systems in various premises. Suitable for installation into supply or air handling units to provide air cooling.DESIGN
Galvanized steel casing. The cooling elements are made of copper tubes and aluminum plates. Available in three-coil modifications and rated for operation with R123, R134a, R152a, R404a, R407c, R410a, R507, R12, R22, R32 refrigerants. Polypropylene droplet separator and drain pan for condensate drainage and removal included. Droplet separator operates efficiently at air flow below 4 m/s.
Only horizontal mounting by means of flanged connection. Condensate drainage must be provided. Air filter must be installed upstream of the cooling unit to prevent the unit soiling. Mounting position must ensure uniform air flow distribution through the entire cross section. Installation upstream or downstream of the supply fan. The minimum air duct length downstream of the fan must be 1-1.5 m to ensure air flow stabilization. The maximum cooling capacity is attained if the cooling unit is connected on counter-flow basis. The attached charts are valid for counter-flow connection. While mounting the cooling unit provide condensate drainage through the U-trap. The U-trap height must be selected with respect to the total fan pressure, refer to the table and diagram below.
For a proper and safe operation of the cooling unit it should be connected to a control system for integral control and automatic cooling capacity regulation.
|Parameter||KFK 80х50-3||Measurement unit|
|Casing material||galvanized steel||-|
|Air duct||for rectangular air ducts||-|
|Series||Flange size (WxH) [cm]||Number of coil rows|
|KFK||40x20; 50x25; 50x30; 60x30; 60x35; 70x40; 80x50; 90x50 100x50||–||3|
|Model||Overall dimensions [mm]|
|Ø D1||Ø D2||B||B1||B2||H||H1||H2||L|
|How to use diagrams.Sample parameters: Air flow = 6000 m³/h.The air flow is 6000 m³/h and the air speed in the cooling unit is 4.35 m/s ①.|
|To calculate the coldest air temperature find the intersection point of the air flow line ① with the rated outer summer temperature shown in blue line (e.g., +30 °С) and draw the line ② to the left until it crosses the outdoor air humidity curve (e.g. 50 %). From this point draw a vertical line to the supply air temperature downstream of the cooling unit (+21 °С) ③. To calculate the power of the cooling unit find the intersection point of the air flow ① with the rated summer temperature (e.g., +30 °С) and draw the line ④ to the right until it crosses the air humidity curve (e.g., 50 %). From this point draw a vertical line to the cooling unit power axis (25.5 kW) ⑤.||To define the necessary refrigerant flow through the cooling unit drop a perpendicular ⑥ on the axis which corresponds to refrigerant flow through the cooling unit (605 kg/h). To define refrigerant pressure drop in the cooling unit find the intersection point of line ⑥ with the pressure drop chart and draw a perpendicular ⑦ to the right until it crosses the refrigerant pressure axis (26.0 kPa).|